Ultimate space simulation software

Mr. Abner
Pioneer
Posts: 377
Joined: 08 Jun 2017
Location: Mississauga

### Physical simulation of the space engine

ethos wrote:
Mr. Abner wrote:
ethos wrote:
Source of the post Is there a FOV that shows actual scale?

That depends on the size of your monitor and how far away your eyes are from it. Basic trigonometry.

It's 13.5 in tall and I'm about 25 in away from it.

Edit: Sorry, my mistake. After a quick flight in SE, it does indeed appear that the FoV is from top to bottom of the screen, not left to right. The formula below still works, but use the monitor height rather than the width. I have edited were appropriate.

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I believe S.E. displays FoV from side to side, so width of the monitor counts, not the height.

You have two right-angle triangles — from the center of your eyes to the middle of the monitor would be the "adjacent" side, from the center of the monitor to one of the side edges either the top or the bottom (or half the width height of your monitor) would be the "opposite" side.

Opposite over adjacent gives you the tangent of the angle between the "adjacent" side and the hypotenuse (which is from your eyes to the edge of the monitor).  So ((arctan of half the width height of the monitor divided by the distance from it) times two) will give the angle from your perspective from one side of the the top of the monitor to the other bottom. Set the FoV to that value, and your monitor should be the equivalent of an actual window into the SE universe.

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So in your actual case, 13.5/2 = 6.75

6.75/25 = 0.27

arctan 0.27 = 15.1096

Times 2 = 30.2192 degrees.

I hope I haven't made an embarrassing error in my math.

ethos
Observer
Posts: 5
Joined: 07 Feb 2019

### Physical simulation of the space engine

[quote="Mr. Abner"][quote="ethos"][quote="Mr. Abner"]
That depends on the size of your monitor and how far away your eyes are from it. Basic trigonometry.[/quote]

It's 13.5 in tall and I'm about 25 in away from it.[/quote]
Edit: Sorry, my mistake. After a quick flight in SE, it does indeed appear that the FoV is from top to bottom of the screen, not left to right. The formula below still works, but use the monitor height rather than the width. I have edited were appropriate.

-----------------------

[s]I believe S.E. displays FoV from side to side, so width of the monitor counts, not the height.[/s]

You have two right-angle triangles — from the center of your eyes to the middle of the monitor would be the "adjacent" side, from the center of the monitor to [s]one of the side edges[/s] either the top or the bottom (or half the [s]width[/s] height of your monitor) would be the "opposite" side.

Opposite over adjacent gives you the tangent of the angle between the "adjacent" side and the hypotenuse (which is from your eyes to the edge of the monitor).  So ((arctan of half the [s]width[/s] height of the monitor divided by the distance from it) times two) will give the angle from your perspective from [s]one side of the[/s] the top of the monitor to the [s]other[/s] bottom. Set the FoV to that value, and your monitor should be the equivalent of an actual window into the SE universe.

------------------

So in your actual case, 13.5/2 = 6.75

6.75/25 = 0.27

arctan 0.27 = 15.1096

Times 2 = 30.2192 degrees.

I hope I haven't made an embarrassing error in my math. [/quote]

Do you need to convert from inches to cm first?

Shaggy
Observer
Posts: 11
Joined: 30 Aug 2017

### Physical simulation of the space engine

[quote="ethos"]
Cool, thats much better. Is there a FOV that shows actual scale? Meaning if I was far enough away from Mercury in real life to appear a certain size to me, the Sun would be accurately be shown in size and scale as well?[/quote]

I think that would be FOV of 0. That's because you can never have Mercury being closer to camera in same scale as sun being farther from camera unless you use ortographic view. As all the 3D games (with exception of some RTS or other top-down view games) SE uses perspective, not ortographic view.

Mr. Abner
Pioneer
Posts: 377
Joined: 08 Jun 2017
Location: Mississauga

### Physical simulation of the space engine

ethos wrote:
Source of the post Do you need to convert from inches to cm first?

Not at all. Trigonometry is really all about ratios. As long as the linear measurements are both in the same units, the ratio of the two will still be the same.

As for actual scale of Mercury and the Sun... if you mean as they look from Earth, then the FoV doesn't actually matter, just make sure you are about 1AU from the Sun. At that distance, the relative size of the Sun and Mercury will be as seen from Earth. You can then use the FoV as a zoom.

If you mean you want to see how big the Sun will look from Mercury, then set the FoV as described above, park yourself on Mercury, and break out the sunglasses. And cold drinks. And sunblock.

longname
Space Pilot
Posts: 143
Joined: 13 Apr 2017
Location: ∞/The Multiverse/The Universe/Local Cluster/The Milky Way/Orion Arm/Sol System/Earth-Moon/Earth/UK

### Physical simulation of the space engine

ethos wrote:
Is there something "off" with the scale of things? For example I'm trying to recreate the transit of Mercury as seen in this actual image.

however is SE, if I move away from Mercury far enough to make it appear as small as that in the image, the Sun is only slightly larger than Mercury is. Am i doing something wrong?

That picture was taken from Earth. Zoom into the Sun using Shift+LMB.
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